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5x-x^2+150=0
We add all the numbers together, and all the variables
-1x^2+5x+150=0
a = -1; b = 5; c = +150;
Δ = b2-4ac
Δ = 52-4·(-1)·150
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-25}{2*-1}=\frac{-30}{-2} =+15 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+25}{2*-1}=\frac{20}{-2} =-10 $
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